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feat: supports docker compose deployment
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docker/examples/sqls/test_case.md
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docker/examples/sqls/test_case.md
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# 测试问题
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## 场景一
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学校管理系统,主要测试SQL助手的联合查询,条件查询和排序功能。
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我们的数据库有三个表:学生表、课程表和成绩表。我们要测试SQL助手能否处理复杂的SQL查询,包括连接多个表,按照一定的条件筛选数据,以及对结果进行排序。
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### Q1
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查询所有学生的姓名,专业和成绩,按成绩降序排序
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SQL:
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```sql
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SELECT students.student_name, students.major, scores.score
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FROM students
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JOIN scores ON students.student_id = scores.student_id
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ORDER BY scores.score DESC;
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```
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### Q2
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查询 "计算机科学" 专业的学生的平均成绩
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SQL:
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```sql
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SELECT AVG(scores.score) as avg_score
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FROM students
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JOIN scores ON students.student_id = scores.student_id
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WHERE students.major = '计算机科学';
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```
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### Q3
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查询哪些学生在 "2023年春季" 学期的课程学分总和超过2学分
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```sql
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SELECT students.student_name
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FROM students
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JOIN scores ON students.student_id = scores.student_id
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JOIN courses ON scores.course_id = courses.course_id
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WHERE scores.semester = '2023年春季'
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GROUP BY students.student_id
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HAVING SUM(courses.credit) > 2;
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```
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## 场景二:电商系统,主要测试SQL助手的数据聚合和分组功能。
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我们的数据库有三个表:用户表、商品表和订单表。我们要测试SQL助手能否处理复杂的SQL查询,包括对数据进行聚合和分组。
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### Q1
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查询每个用户的总订单数量
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SQL:
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```sql
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SELECT users.user_name, COUNT(orders.order_id) as order_count
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FROM users
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JOIN orders ON users.user_id = orders.user_id
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GROUP BY users.user_id;
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```
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### Q2
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查询每种商品的总销售额
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```sql
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SELECT products.product_name, SUM(products.product_price * orders.quantity) as total_sales
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FROM products
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JOIN orders ON products.product_id = orders.product_id
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GROUP BY products.product_id;
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```
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### Q3
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查询2023年最受欢迎的商品(订单数量最多的商品)
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```sql
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SELECT products.product_name
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FROM products
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JOIN orders ON products.product_id = orders.product_id
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WHERE YEAR(orders.order_date) = 2023
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GROUP BY products.product_id
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ORDER BY COUNT(orders.order_id) DESC
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LIMIT 1;
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```
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