[Update] 控制是否显示未分组节点

This commit is contained in:
ibuler
2019-08-08 13:03:03 +08:00
parent c3a206b291
commit 6b56c43a3a
5 changed files with 23 additions and 1 deletions

View File

@@ -180,6 +180,19 @@ class GenerateTree:
assets.append({"id": asset_id, "system_users": system_users})
return assets
def set_ungrouped_assets_nodes_if_need(self):
if settings.PERM_SINGLE_ASSET_TO_UNGROUP_NODE:
return
ungrouped_assets_ids = self.nodes[self.ungrouped_key]["assets"]
for asset_id in ungrouped_assets_ids:
in_nodes = self.all_assets_nodes_keys.get(asset_id, [])
for node_key in in_nodes:
parents_keys = self.node_util.get_nodes_parents_keys_by_key(node_key, with_self=False)
for parent_key in parents_keys:
n = self.nodes[parent_key]
self.nodes[node_key]["assets"].add(asset_id)
self.nodes.pop(self.ungrouped_key, None)
@timeit
def get_nodes_with_assets(self):
"""
@@ -198,6 +211,7 @@ class GenerateTree:
"""
if self._nodes_with_assets:
return self._nodes_with_assets
self.set_ungrouped_assets_nodes_if_need()
util = PermAssetsAmountUtil()
nodes_with_assets_amount = util.compute_nodes_assets_amount(self.nodes)
nodes = []
@@ -219,6 +233,7 @@ class GenerateTree:
return nodes
def get_nodes(self):
self.set_ungrouped_assets_nodes_if_need()
nodes = list(self.nodes.keys())
if not nodes:
nodes.append(const.EMPTY_NODE_KEY)