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bash: compare numbers numerically, not lexically

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Thanks, bash, for supporting < and > and making them NOT mean the obvious thing.

[[ 2 < 10 ]] is false
(( 2 < 10 )) is true
This commit is contained in:
Tim Hockin 2023-03-05 15:14:43 -08:00
parent bbbbfcd967
commit fe96e5704f
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1 changed files with 2 additions and 2 deletions
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4
hack/lib/logging.sh
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@ -130,7 +130,7 @@ kube::log::usage_from_stdin() {
# Print out some info that isn't a top level status line # Print out some info that isn't a top level status line
kube::log::info() { kube::log::info() {
local V="${V:-0}" local V="${V:-0}"
if [[ ${KUBE_VERBOSE} < ${V} ]]; then if (( KUBE_VERBOSE < V )); then
return return
fi fi
@ -158,7 +158,7 @@ kube::log::info_from_stdin() {
# Print a status line. Formatted to show up in a stream of output. # Print a status line. Formatted to show up in a stream of output.
kube::log::status() { kube::log::status() {
local V="${V:-0}" local V="${V:-0}"
if [[ ${KUBE_VERBOSE} < ${V} ]]; then if (( KUBE_VERBOSE < V )); then
return return
fi fi