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langchain: add id_key option to EnsembleRetriever for metadata-based document merging (#22950)
**Description:** - What I changed - By specifying the `id_key` during the initialization of `EnsembleRetriever`, it is now possible to determine which documents to merge scores for based on the value corresponding to the `id_key` element in the metadata, instead of `page_content`. Below is an example of how to use the modified `EnsembleRetriever`: ```python retriever = EnsembleRetriever(retrievers=[ret1, ret2], id_key="id") # The Document returned by each retriever must keep the "id" key in its metadata. ``` - Additionally, I added a script to easily test the behavior of the `invoke` method of the modified `EnsembleRetriever`. - Why I changed - There are cases where you may want to calculate scores by treating Documents with different `page_content` as the same when using `EnsembleRetriever`. For example, when you want to ensemble the search results of the same document described in two different languages. - The previous `EnsembleRetriever` used `page_content` as the basis for score aggregation, making the above usage difficult. Therefore, the score is now calculated based on the specified key value in the Document's metadata. **Twitter handle:** @shimajiroxyz
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@ -66,11 +66,14 @@ class EnsembleRetriever(BaseRetriever):
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c: A constant added to the rank, controlling the balance between the importance
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of high-ranked items and the consideration given to lower-ranked items.
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Default is 60.
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id_key: The key in the document's metadata used to determine unique documents.
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If not specified, page_content is used.
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"""
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retrievers: List[RetrieverLike]
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weights: List[float]
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c: int = 60
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id_key: Optional[str] = None
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@property
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def config_specs(self) -> List[ConfigurableFieldSpec]:
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@ -305,13 +308,24 @@ class EnsembleRetriever(BaseRetriever):
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rrf_score: Dict[str, float] = defaultdict(float)
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for doc_list, weight in zip(doc_lists, self.weights):
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for rank, doc in enumerate(doc_list, start=1):
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rrf_score[doc.page_content] += weight / (rank + self.c)
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rrf_score[
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doc.page_content
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if self.id_key is None
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else doc.metadata[self.id_key]
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] += weight / (rank + self.c)
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# Docs are deduplicated by their contents then sorted by their scores
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all_docs = chain.from_iterable(doc_lists)
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sorted_docs = sorted(
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unique_by_key(all_docs, lambda doc: doc.page_content),
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unique_by_key(
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all_docs,
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lambda doc: doc.page_content
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if self.id_key is None
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else doc.metadata[self.id_key],
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),
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reverse=True,
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key=lambda doc: rrf_score[doc.page_content],
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key=lambda doc: rrf_score[
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doc.page_content if self.id_key is None else doc.metadata[self.id_key]
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],
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)
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return sorted_docs
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88
libs/langchain/tests/unit_tests/retrievers/test_ensemble.py
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88
libs/langchain/tests/unit_tests/retrievers/test_ensemble.py
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@ -0,0 +1,88 @@
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from typing import List, Optional
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from langchain_core.callbacks.manager import CallbackManagerForRetrieverRun
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from langchain_core.documents import Document
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from langchain_core.retrievers import BaseRetriever
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from langchain.retrievers.ensemble import EnsembleRetriever
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class MockRetriever(BaseRetriever):
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docs: List[Document]
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def _get_relevant_documents(
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self,
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query: str,
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*,
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run_manager: Optional[CallbackManagerForRetrieverRun] = None,
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) -> List[Document]:
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"""Return the documents"""
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return self.docs
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def test_invoke() -> None:
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documents1 = [
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Document(page_content="a", metadata={"id": 1}),
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Document(page_content="b", metadata={"id": 2}),
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Document(page_content="c", metadata={"id": 3}),
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]
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documents2 = [Document(page_content="b")]
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retriever1 = MockRetriever(docs=documents1)
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retriever2 = MockRetriever(docs=documents2)
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ensemble_retriever = EnsembleRetriever(
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retrievers=[retriever1, retriever2], weights=[0.5, 0.5], id_key=None
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)
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ranked_documents = ensemble_retriever.invoke("_")
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# The document with page_content "b" in documents2
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# will be merged with the document with page_content "b"
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# in documents1, so the length of ranked_documents should be 3.
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# Additionally, the document with page_content "b" will be ranked 1st.
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assert len(ranked_documents) == 3
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assert ranked_documents[0].page_content == "b"
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documents1 = [
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Document(page_content="a", metadata={"id": 1}),
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Document(page_content="b", metadata={"id": 2}),
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Document(page_content="c", metadata={"id": 3}),
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]
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documents2 = [Document(page_content="d")]
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retriever1 = MockRetriever(docs=documents1)
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retriever2 = MockRetriever(docs=documents2)
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ensemble_retriever = EnsembleRetriever(
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retrievers=[retriever1, retriever2], weights=[0.5, 0.5], id_key=None
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)
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ranked_documents = ensemble_retriever.invoke("_")
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# The document with page_content "d" in documents2 will not be merged
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# with any document in documents1, so the length of ranked_documents
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# should be 4. The document with page_content "a" and the document
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# with page_content "d" will have the same score, but the document
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# with page_content "a" will be ranked 1st because retriever1 has a smaller index.
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assert len(ranked_documents) == 4
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assert ranked_documents[0].page_content == "a"
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documents1 = [
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Document(page_content="a", metadata={"id": 1}),
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Document(page_content="b", metadata={"id": 2}),
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Document(page_content="c", metadata={"id": 3}),
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]
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documents2 = [Document(page_content="d", metadata={"id": 2})]
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retriever1 = MockRetriever(docs=documents1)
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retriever2 = MockRetriever(docs=documents2)
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ensemble_retriever = EnsembleRetriever(
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retrievers=[retriever1, retriever2], weights=[0.5, 0.5], id_key="id"
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)
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ranked_documents = ensemble_retriever.invoke("_")
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# Since id_key is specified, the document with id 2 will be merged.
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# Therefore, the length of ranked_documents should be 3.
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# Additionally, the document with page_content "b" will be ranked 1st.
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assert len(ranked_documents) == 3
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assert ranked_documents[0].page_content == "b"
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